Equations.
$\vec{v}=\dfrac{\Delta \vec{x}}{\Delta t}$
$\vec{a}=\dfrac{\Delta \vec{v}}{\Delta t}$
$v_x=v_{x0}+a_xt$
$x=x_0+v_{x0}t+\tfrac{1}{2}a_xt^2$
$v_x^2=v_{x0}^2+2a_x(x-x_0)$
$\vec{x}_{cm}=\dfrac{\sum m_i\vec{x}_i}{\sum m_i}$
$\vec{a}=\dfrac{\sum\vec{F}}{m}$
$\vec{F}_{A\text{ on }B}=-\vec{F}_{B\text{ on }A}$
$F_g=G\dfrac{m_1m_2}{r^2}$
$|\vec{g}|=\dfrac{F_g}{m}$
$|\vec{F}_{f,k}|=\mu_k|\vec{F}_n|$
$|\vec{F}_{f,s}|\le\mu_s|\vec{F}_n|$
$\vec{F}_s=-k\Delta\vec{x}$
$a_c=\dfrac{v^2}{r}$
$T=\dfrac{2\pi r}{v}$
$K=\tfrac{1}{2}mv^2$
$W=\vec{F}\cdot\Delta\vec{r}=F\Delta r\cos\theta$
$\Delta U_g=mg\Delta y$
$U_s=\tfrac{1}{2}k(\Delta x)^2$
$\Delta E=W$
$P=\dfrac{\Delta E}{\Delta t}$
$\vec{p}=m\vec{v}$
$\Delta\vec{p}=\vec{F}\Delta t$
Given.
$\vec{a}_g=-9.80665\,\hat{\jmath}$ m/s$^2$, which may be taken as $10$ N/kg
$G=6.67\times10^{-11}$ N$\cdot$m$^2$/kg$^2$
Air resistance is negligible throughout.
This is the same reference information printed at the top of the paper version of this test. Nothing else is provided.